if he started with h heads of lettuce, and sold s,
end of Monday he had h-s
on Tuesday, he had 2(h-s) and sold s, leaving 2h-3s
On Wednesday, he had 3(2h-3s) and sold s, leaving 0.
6h-9s-s = 0
6h = 10s
So, he started out with some multiple of 10 and 6, let's say 30
h=5,s=3
Monday: start with 5, sold 3, leaving 2
Tuesday: start with 4, sold 3, leaving 1
Wednesday: start with 3, sold 3.
Or, he could have started out with
150, so h=25, s=15
Monday: start with 25, sold 15, leaving 10
Tuesday: start with 20, sold 15, leaving 5
Wednesday: start with 15, sold 15.
Monday, Mr. C stacked a display case of 80 heads of lettuce. By end of day, some were sold.
Tuesday Mr. C counted lettuce left and decided to add an equal number of lettuce (**hint - he doubled the leftovers). At end of Tuesday, he sold the same number as Monday.
Wednesday Mr. C tripled lettuce left. He sold the same number that day too. At end of day, there were no lettuce left.
How manylettuce were sold each day?
Please help, I would appreciate guidance on this.
Thx
3 answers
Oops. I forgot that he started with 80.
So,
6*80 = 10s
s = 48
Start with 80, sold 48, leaving 32
Tuesday: start with 64, sold 48, leaving 16
Wednesday: start with 48, sold 48.
So,
6*80 = 10s
s = 48
Start with 80, sold 48, leaving 32
Tuesday: start with 64, sold 48, leaving 16
Wednesday: start with 48, sold 48.
Thanks!This really helped
3 answers