The market sold 24 heads of lettuce one morning. That afternoon 2/7 of the remaining heads of lettuce were sold. The number of heads left now was 1/2 of ye numbet the market haf at the beginning of yhe day. How many heads of lettuce were there at the beginning of the day.

Answer 1

X Heads to start with.
(X-24) = Bal.

(X-24) - 2/7(X-24) = 5/7(x-24).

5/7(X-24) = X/2
Multiply both sides by 14:
10x-240 = 7x
3x = 240
X = 80 Heads of lettuce.

Answer 2

I don't get this too, can you help me too? Im a fifth grader too so I cant do Algebra.

Answer 3

24 {heads of lettuce} x 2/7 [percentage sold in the afternoon] = 48
48 x 5/7 [amount remaining] = 240/7
(240/7) divided by (3/7)[remainder of 5/7-2/7=3/7]
240/7 x 7/3
= 240 divided by 3 = 80 heads of lettuce [the 7's cancels out]

ANSWER 80 HEADS OF LETTUCE