The incorrect step in Misha's proof is:
Step 3 is incorrect. The lines do not need to have a point of intersection since they are not parallel.
In Misha's proof, she assumes two distinct lines \( l \) and \( n \) with the same slope \( m \) and that they are not parallel. However, non-parallel lines by definition either do not intersect (if they are parallel) or they intersect at exactly one point (if they are different lines with different slopes). Since she posits that they have the same slope but are not parallel, this leads to a contradiction because lines that share the same slope must indeed be parallel and therefore cannot intersect. Thus, her assumption about the intersection is incorrect.