Ming has 12 unsharpened pencils bundled in the shape of a cylinder. If the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming’s bundle of pencils? Use 3.14 for π and round to the nearest tenth.???

Answer 1

The surface area of a cylinder is calculated using the formula:

Surface Area = 2πr^2 + 2πrh

where r is the radius of the base of the cylinder and h is the height of the cylinder.

Given that the diameter is 0.5 cm, the radius is half of the diameter, so r = 0.25 cm.
The height of the cylinder is given as 19 cm.

Surface Area = 2(3.14)(0.25)^2 + 2(3.14)(0.25)(19)
Surface Area = 2(3.14)(0.0625) + 2(3.14)(0.25)(19)
Surface Area = 2(0.19625) + 2(3.14)(4.75)
Surface Area = 0.3925 + 29.86
Surface Area = 30.2525 cm^2

Therefore, the surface area of Ming's bundle of pencils is approximately 30.3 cm^2 when rounded to the nearest tenth.

Answer 2

wrong

Answer 3

My apologies for the error.

Let's try the calculation again:

The formula to calculate the surface area of the cylinder is:

Surface Area = 2πr(r + h)

Given that the radius (r) is 0.25 cm and the height (h) is 19 cm:

Surface Area = 2 * 3.14 * 0.25(0.25 + 19)
Surface Area = 2 * 3.14 * 0.25(19.25)
Surface Area = 2 * 3.14 * 4.8125
Surface Area = 30.2225 cm^2

Rounded to the nearest tenth, the surface area of Ming's bundle of pencils is 30.2 cm^2.