To find the surface area of the bundle of pencils (cylinder), we need to calculate the lateral surface area and the two circular bases.
1. Lateral Surface Area:
Lateral Surface Area = 2 * π * radius * height
Radius = diameter / 2 = 0.5 cm / 2 = 0.25 cm
Lateral Surface Area = 2 * 3.14 * 0.25 cm * 19 cm
Lateral Surface Area = 2 * 3.14 * 0.25 cm * 19 cm
Lateral Surface Area = 2 * 3.14 * 0.25 cm * 19 cm
Lateral Surface Area = 11.9 cm^2
2. Circular Base Area:
Each circular base has an area of π * radius^2
Base Area = 3.14 * 0.25 cm^2 = 0.785 cm^2
Total Base Area = 2 * 0.785 cm^2 = 1.57 cm^2
Total Surface Area = Lateral Surface Area + 2(Base Area)
Total Surface Area = 11.9 cm^2 + 1.57 cm^2
Total Surface Area = 13.47 cm^2
Therefore, the surface area of Ming's bundle of pencils is 13.47 cm^2.
Ming had 13 unsharpened pencils bundled in the shape of a cylinder. Of the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming's bundle of pencils? Use 3.14 for π and round to the nearest tenth
It is NOT 30.3
1 answer
1 answer