First, we need to find the surface area of the two circular ends of the cylinder.
The formula for the surface area of a circle is A = πr^2, where r is the radius of the circle. Since the diameter is 0.5 cm, the radius is 0.25 cm.
A = 3.14 * (0.25)^2
A = 3.14 * 0.0625
A = 0.19625 cm^2 (surface area of one circular end)
Since there are two ends, the total surface area of the circular ends is 2 * 0.19625 = 0.3925 cm^2.
Next, we need to find the lateral surface area of the cylinder. The formula for the lateral surface area is A = 2πrh, where r is the radius and h is the height (length).
A = 2 * 3.14 * 0.25 * 19
A = 3.14 * 0.5 * 19
A = 29.83 cm^2
The total surface area of Ming's bundle of pencils is the sum of the surface areas of the two circular ends and the lateral surface area:
Total Surface Area = 0.3925 + 29.83
Total Surface Area = 30.22 cm^2
Therefore, the surface area of Ming's bundle of pencils is 30.2 cm^2.
Ming had 13 unsharpened pencils bundled in the shape of a cylinder. Of the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming's bundle of pencils? Use 3.14 for π and round to the nearest tenth
It is not 30.3 nor is it 13.47
1 answer
1 answer