Micah Beasley invested $10,000 for one year, part at 10% annual interest and part at 14% annual interest. Vos total interest for the year was $1,280. How much money did he invest at each rate?

Answer 1

let the part invested at 10% be x
let the part invested at 14% be 10000-x

solve for x

.1x + .14(10000-x) = 1280

let me know what you get, so I can check it

Answer 2

x at 10%, and y at 14%

x + y = 10000

.10 x + .14 y = 1280 ... multiplying by -10 ... -x - 1.4y = -12800

adding equations (to eliminate x) ... -.4 y = -2800

solve for y , then substitute back to find x

Answer 3

thank toi!