0.00082 mols Mg x (1 mol H2/1 mol Mg) = 0.00082 x 1/1 = mols H2.
grams H2 = mols H2 x molar mass H2.
Mg+2HCl--->MgCl2+H2
Using the balanced equation, how many moles of H2 will you make if you start with .00082 moles of Mg solid? How many grams of H2 is that?
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