7 people
5 Doctors taken 2 at a time
C(5,2) = 5! / [ 2! (5-2)! ] = (5*4* 3) / 3*2 = 10 combinations of doctors
4 nurses, 2 at a time
C(4,2) = 4!/ [ 2! * 2!]= 4*3*2 / 4 = 6
6*10 = 60
Members of a hospital advisory committee will be selected from 5 doctors and 4 nurses. The committee must have 2 doctors and 2 nurses.
How many possible combinations of doctors and nurses could be chosen for the committee????
1 answer
1 answer