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Megan factored the expression (-12x^2+52x-35) as (-2x+5)(6x-7) but when Jacob applied FOIL principle and multiplied out (2x+5)(...Asked by sam
                Megan factored the expression (-12x^2+52x-35) as (-2x+5)(6x-7) but when Jacob applied FOIL principle and multiplied out (2x+5)(6x-7) he got (-12x^2+44x-35),thus megan's solution does not appear to check please help megan to understand better.Explain your reasoning and correctly factor the original expression if possible If the expression is a prime please state so
            
            
        Answers
                    Answered by
            Reiny
            
    First of all I changed it into
- (12x^2 - 52x + 35)
After 4 tries I had
- (2x-7)(6x-5) or (7-2x)(6x-5) or (2x-7)(5-6x)
(I use a method where I list the factors of the first and last numbers, and then take sum or differences of cross-products
e.g.
3 <b>2</b> 1 ....... 5 <b>7</b>
4 <b>6</b> 12 ...... 7 <b>5</b>
2x5 + 6x7 = 52, my middle term
This is the fastest way to factor trinomials, too bad nobody seems to teach this method any more.
    
- (12x^2 - 52x + 35)
After 4 tries I had
- (2x-7)(6x-5) or (7-2x)(6x-5) or (2x-7)(5-6x)
(I use a method where I list the factors of the first and last numbers, and then take sum or differences of cross-products
e.g.
3 <b>2</b> 1 ....... 5 <b>7</b>
4 <b>6</b> 12 ...... 7 <b>5</b>
2x5 + 6x7 = 52, my middle term
This is the fastest way to factor trinomials, too bad nobody seems to teach this method any more.
                    Answered by
            sam
            
    I came up with -(6x-5)(2x-7)
    
                    Answered by
            Reiny
            
    yes, 
that was my first answer I gave you.
surely you realize that
-(6x-5)(2x-7) = - (2x-7)(6x-5)
    
that was my first answer I gave you.
surely you realize that
-(6x-5)(2x-7) = - (2x-7)(6x-5)
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