To complete the proof that all three medians of a triangle intersect at a single point (the centroid), we can fill in the missing pieces step by step.
Step 1:
Draw the three medians of the triangle.
- Drag each median so that it starts at a vertex and ends at the midpoint of the opposite side.
Step 2:
Find the coordinates of each midpoint by taking the sum of the x-coordinates and dividing by 2 and taking the sum of the y-coordinates and dividing by 2.
- The midpoint between (0, 0) and (b, c) is \(\left(\frac{b}{2}, \frac{c}{2}\right)\).
- The midpoint of (0, 0) and (a, 0) is \(\left(\frac{a}{2}, 0\right)\).
- The midpoint of (a, 0) and (b, c) is \(\left(\frac{a + b}{2}, \frac{c}{2}\right)\).
Step 3:
Find the coordinates of P, the point where the medians appear to intersect, on each median. Use the formula.
- The formula for a point dividing a segment in the ratio m:n is given by \(\left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right)\).
Step 4:
Find the coordinates of P on the median that starts at vertex (0, 0) and ends at midpoint \(\left(\frac{a + b}{2}, \frac{c}{2}\right)\):
- For median from (0, 0) to \(\left(\frac{a + b}{2}, \frac{c}{2}\right)\):
- \(P = \frac{1}{3}(0, 0) + \frac{2}{3}\left(\frac{a + b}{2}, \frac{c}{2}\right) = \left(0 + \frac{2(a + b)}{6}, 0 + \frac{2c}{6}\right) = \left(\frac{a + b}{3}, \frac{c}{3}\right)\).
Find the coordinates of P on the median that starts at vertex (a, 0) and ends at midpoint \(\left(\frac{b}{2}, \frac{c}{2}\right)\):
- For median from (a, 0) to \(\left(\frac{b}{2}, \frac{c}{2}\right)\):
- \(P = \frac{1}{3}(a, 0) + \frac{2}{3}\left(\frac{b}{2}, \frac{c}{2}\right) = \left(\frac{a}{3} + \frac{b}{3}, \frac{c}{3}\right) = \left(\frac{a + b}{3}, \frac{c}{3}\right)\).
Find the coordinates of P on the median that starts at vertex (b, c) and ends at midpoint \(\left(\frac{a}{2}, 0\right)\):
- For median from (b, c) to \(\left(\frac{a}{2}, 0\right)\):
- \(P = \frac{1}{3}(b, c) + \frac{2}{3}\left(\frac{a}{2}, 0\right) = \left(\frac{b}{3} + \frac{a}{3}, \frac{c}{3}\right) = \left(\frac{a + b}{3}, \frac{c}{3}\right)\).
Step 5:
The coordinates of P on each median are \(\left(\frac{a + b}{3}, \frac{c}{3}\right)\), which proves that the three medians of this generic triangle all intersect at the same point.
By filling in these responses, we complete the proof that the three medians in a triangle meet at a single point, known as the centroid.