Question

Many power plants produce energy by burning carbon-based fuels, which also produces CO2. CO2 is a greenhouse gas, so over-production can have negative effects on the environment.
Use enthalpy of formation data to calculate the number of moles of CO2 (g) produced per mega joule of heat released from the combustion of each fuel under standard conditions.
a) Coal c (s, graphite)
b) Natural gas, CH4 (g)
c) propane, C3H8 (g)
d) Octane, C8H18 (l) delta H f = -250 kJ Mol -1

Answer 1

someone should answer this question please

Answer 2

a) 2.54
b) 1.12
c) 1.35
d) 1.46

Answer 3

Batman is correct.

Answer 4

Batman is indeed correct.

Answer 5

First write out the combustion reaction.
Second calculate the energy released (delta Hf).
Third divide 1MJ = 1000kJ by the energy released in step 2 to obtain the number of complete reactions needed to release 1MJ.
Fourth, multiply by the coefficient of CO2, to get the moles of CO2 produced in total for all the reactions in step 3.

Batman very much so has the correct answers.

Answer 6

batman saved me

Answer 7

typical batman. saving the day, as per usual.

Answer 8

Spiderman saved the day too by explaining how to do it!

Answer 9

TANK U BATMAN

Answer 10

thanks guys for the great help

Answer 11

BATMAN, you haved failed to explain yourself yet again! But thanks spider man, you're a much cooler hero... obviously...

Answer 12

Thank you Batman. I am forever in your debt. And thanks my friendly neighborhood Spiderman for helping me understand!

Answer 13

My teacher didn't do a good job explaining, help please!

Answer 14

Can someone write out the combustion reaction?

Answer 15

Okay, First write out all of the balanced equations of combustion(A combustion equation is just adding O2 to the reactant, and ending with CO2 in the products. Notice, if H is in the reactants, you'll need H2O to balance the products:
Coal:
C+O2-->CO2
Natural Gas:
CH4+2O2-->CO2+2H2O
Propane:
C3H8+5O2-->3CO2+4H2O
Octane:
2C8H18+25O2-->16CO2+18H2O

Then find the energy released for both the products and the reactants. Since Octane was given to us in the question, I'll use that as an example for the equation:
[2C8H18(-250.1)+25O2(0)]-[16CO2(-393.5)+18H2O(-285.8)] = 10940.2 KJ
(assuming reaction is under standard conditions of 1 atm, and about 25 deg C.)
Now take the coefficient of CO2 that was formed in the product and divide it by the number of J found.
(16/10940.2) = 1.46*10^-3

Then multiply it by 1000 KJ to get it into MJ.

(1.46*10^-3)1000 = 1.46 mol/MJ

Answer 16

I disagree with batman. Although his set up is correct the use of the KJ/mol is incorrect. In a combustion reaction all of the products will be in gas, not liquid. The number batman is giving is for liquid H2O, not gaseous H2O. SO if your answer is wrong this is why.

Should be:
a. 2.54 mol/MJ
b. 1.25 mol/MJ
c. 1.47 mol/MJ
d. 1.58 mol/MJ

Answer 17

In response to lobu6058, the deltaHf value for liquid water is correct IF we're assuming standard conditions for this reaction. Specifically, that it is taking place at 25C. Because water is a liquid at 25C, the deltaHf value should be for liquid water. Not all combustion reactions produce gaseous H2O. If the reaction is taking place at 100+C, where water is a gas, then you would use the deltaHf value for gaseous H2O, if it is taking place between 0-99C, where water is a liquid, you use the deltaHf value for liquid H2O.

Answer 18

I am living for the comments haha!

Answer 19

I will kill half of you

Answer 20

I love you batman can you answer all my homework questions

Answer 21

batman!!!! you godly figure

Answer 22

Travis Scott come get your kids!!!!! Where the child support at?

Answer 23

Where were all you superheros when I was happening?

Answer 24

Thanks Batman your cool but Deadpool is cooler...0bviously😎😎😎.