Question

Lulu marks the points (9,1) and (-3,6) on a coordinate plane. What is the distance between these two points, rounded to the nearest tenth of a unit?(1 point) Responses 7.2 units 7.2 units 13.0 units 13.0 units 14.2 units 14.2 units 8.0 units 8.0 units Question 2 What is the midpoint of the segment? If not a whole number, write as a decimal(1 point)

Answer 1

To find the distance between the points \((9,1)\) and \((-3,6)\), we can use the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Here, \((x_1, y_1) = (9, 1)\) and \((x_2, y_2) = (-3, 6)\).

Now substitute the values into the formula:

\[
d = \sqrt{((-3) - 9)^2 + (6 - 1)^2}
\]

Calculating each part:

\[
d = \sqrt{(-12)^2 + (5)^2}
\]

\[
d = \sqrt{144 + 25} = \sqrt{169} = 13
\]

The distance between the points is **13.0 units** (rounded to the nearest tenth).

---

Now, to find the midpoint of the segment connecting these two points, we use the midpoint formula:

\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

Substituting in the coordinates:

\[
\text{Midpoint} = \left( \frac{9 + (-3)}{2}, \frac{1 + 6}{2} \right)
\]

Calculating each part:

\[
\text{Midpoint} = \left( \frac{6}{2}, \frac{7}{2} \right) = \left( 3, 3.5 \right)
\]

Therefore, the midpoint of the segment is **(3, 3.5)**.