Question

Lulu marks the points (9,1) and (-3,6) on a coordinate plane. What is the distance between these two points, rounded to the nearest tenth of a unit?

Answer 1

What the mid point

Answer 2

Mb thought I was replying to my own thing now I look stupid

Answer 3

To find the distance between the points \( (9, 1) \) and \( (-3, 6) \), we can use the distance formula, which is given by

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Here, we set:
- \( (x_1, y_1) = (9, 1) \)
- \( (x_2, y_2) = (-3, 6) \)

Now, we substitute the coordinates into the formula:

\[
d = \sqrt{((-3) - 9)^2 + (6 - 1)^2}
\]

Calculating \( (-3) - 9 \) gives us:

\[
-3 - 9 = -12
\]

Now, squaring it:

\[
(-12)^2 = 144
\]

Next, we calculate \( 6 - 1 \):

\[
6 - 1 = 5
\]

Now, squaring this value:

\[
5^2 = 25
\]

Now, we substitute these squared values back into the distance formula:

\[
d = \sqrt{144 + 25}
\]

Adding the two values inside the square root:

\[
144 + 25 = 169
\]

Taking the square root gives us:

\[
d = \sqrt{169} = 13
\]

Thus, the distance between the points \( (9, 1) \) and \( (-3, 6) \) is

\[
\boxed{13.0}
\]

when rounded to the nearest tenth.