Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5

Question

. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

2.5 feet below
2.5 feet below

0 feet above or below
0 feet above or below

5 feet above
5 feet above

5 feet below
5 feet below

Answer 1

To determine how far above or below street level Luca's initial launching point is, we need to evaluate the formula \(y = -16t^2 + 40t - 5\) at \(t = 0\), which represents the moment when Luca launches the object.

Substituting \(t = 0\) into the equation:

\[ y = -16(0)^2 + 40(0) - 5 \] \[ y = -5 \]

This means that 5 feet below street level is the height of Luca's initial launching point.

Therefore, the correct response is:

5 feet below