Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5

Question

. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

5 feet above
5 feet above

2.5 feet below
2.5 feet below

0 feet above or below
0 feet above or below

5 feet below

Answer 1

To analyze the situation and determine how far above or below street level Luca's initial launching point is, we need to examine the equation given:

\[ y = -16t^2 + 40t - 5 \]

In this equation, \( y \) represents the height (in feet) of the object above or below street level at time \( t \) (in seconds). The initial height of the object (Luca's position when \( t = 0 \)) can be found by substituting \( t = 0 \) into the equation:

\[ y(0) = -16(0)^2 + 40(0) - 5 \] \[ y(0) = -5 \]

This means Luca's initial launching point is 5 feet below street level.

So, among the options provided, the correct response is:

5 feet below