Looking at the periodic table, determine the number of valence electrons present in a following neutral atoms.

Question

Column A
1.
Oxygen (O):
Oxygen (O)
2.
Aluminium (Al):
Aluminium (Al)
3.
Neon (Ne):
Neon (Ne)
4.
Silicion (Si):
Silicion (Si)
5.
Magnesium (Mg):
Magnesium (Mg)
6.
Iodine (I):
Iodine (I)
7.
Lithium (Li):
Lithium (Li)
8.
Nitrogen (N):
Nitrogen (N)
Column B
a.8 valence electrons
b.2 valence electrons
c.3 valence electrons
d.7 valence electrons
e.1 valence electrons
f.5 valence electrons
g.6 valence electrons
h.4 valence electrons

Answer 1

Here are the number of valence electrons for each of the specified neutral atoms, matched with the corresponding options from Column B:

1. Oxygen (O): 6 valence electrons - g
2. Aluminium (Al): 3 valence electrons - c
3. Neon (Ne): 8 valence electrons - a
4. Silicon (Si): 4 valence electrons - h
5. Magnesium (Mg): 2 valence electrons - b
6. Iodine (I): 7 valence electrons - d
7. Lithium (Li): 1 valence electron - e
8. Nitrogen (N): 5 valence electrons - f

Here's the summary:

• Oxygen (O): 6 - g
• Aluminium (Al): 3 - c
• Neon (Ne): 8 - a
• Silicon (Si): 4 - h
• Magnesium (Mg): 2 - b
• Iodine (I): 7 - d
• Lithium (Li): 1 - e
• Nitrogen (N): 5 - f