This is (probably) a series with a recurrence relation:
a(n)=a(n-3)+a(n-2)+a(n-1)
Try
0=-1+0+1
1=0+1+0
2=1+0+1
...
37=6+11+20
Some call this tribonacci numbers, from
Fibonacci numbers where
a(n)=a(n-2)+a(n-1)
Look over the following sequence of numbers. What are the next 3 numbers in the pattern?what is the pattern rule?
-1,0,1,0,1,2,3,6,11,20,37
5 answers
Thanks so much
How do get the three numbers relative I understand that the number u get is the first to add for the next in the pattern?
Are the three numbers 63. 89. 115???????
Basically, you add the three last numbers to get the next, for example,
2+3+6=11, ...
So the next number is:
11+20+37 = 68
20+37+68 = ?
...
2+3+6=11, ...
So the next number is:
11+20+37 = 68
20+37+68 = ?
...