not that dificult
logx^2=-8
x^2=3^-8
x^2=3^(-2)^3
power 2 cancel out we have
x=3^-3
x=1/3^3
x=1/27
logx^2{base3}=-8
show that x=1/27
3 answers
or
log3 x^2 = -8
2 log3 x = -8
3 x = -4
x = 3^-4
x = 1/81 not 1/27
check with calculator
if x = 1/27
3 (1/27)^2
= 23 (1/27)
= 2(-3)
= -6
≠ -8
1/81 does check out.
log3 x^2 = -8
2 log3 x = -8
3 x = -4
x = 3^-4
x = 1/81 not 1/27
check with calculator
if x = 1/27
3 (1/27)^2
= 23 (1/27)
= 2(-3)
= -6
≠ -8
1/81 does check out.
oh yeah i did not see that thanks.....