Logv3(12) = logv3 (3t^2) - logv3 (3t)

(the v means "log 3"- 3 is the base)

5 answers

remember to divide the terms when subtracting in logarithms.
WAIT ITS t^2 NOT 3t^2
ok, divide throughout by logv3 and then you will get a quadratic equation and solve for t.
But then when i try to factor i get 0=t^2-3t-12
Complete the square method.
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