take the log base 5 of each side
x-1=log5 9=log10 9 /( log10 5)
http://www.sosmath.com/algebra/logs/log4/log43/log43.html
logarithms
solve for x
5^(x-1) = 9
2 answers
?
can i do
x-1= log9/log6
x=(log9/log5) + 1 ?
can i do
x-1= log9/log6
x=(log9/log5) + 1 ?