Well, with log150 it's log3+log(10)^2-log2
With log75 it is equivalent to log3+log(10)^2-log(2)^2
Hope this helped
My teacher assigned us this problem:
Using the following logarithms
Log2,log3 and log10 solve for the log150,log 75 incorporating the properties of logarithms ,i tried ,but failed plz help!!
2 answers
not quite. log(x^2) = 2logx
150 = 3*100/2, so
log 150 = log3 + 2log10 - log2
75 = 3*(10/2)^2, so
log75 = log3 + 2log10 - 2log2
or, since 75 = 150/2
log75 = log150-log2 as above
150 = 3*100/2, so
log 150 = log3 + 2log10 - log2
75 = 3*(10/2)^2, so
log75 = log3 + 2log10 - 2log2
or, since 75 = 150/2
log75 = log150-log2 as above
1 answer