log3(4x+1)-log3(3x-5)=2
log3( (4x+1)/(3x-5)) = 2
(4x+1)/(3x-5) = 3^2 = 9
27x - 45 = 4x + 1
carry on
log3(4x+1)-log3(3x-5)=2
5 answers
Abigail
If log10y+3log10*=2, Express y in term of x.
Solve the equation log3,4x+1-log3,3x-5=2
Using the logarithmic identity,
log base a (M/N) = log base a M - log base a N,
we can rewrite the given equation as:
log3 (4x+1) - log3 (3x-5) = 2
log3 [(4x+1)/(3x-5)] = 2
3^2 = 9, so we can rewrite the equation as:
(4x+1)/(3x-5) = 9
Multiplying both sides by 3x-5, we get:
4x + 1 = 9(3x-5)
Simplifying and solving for x, we get:
4x + 1 = 27x - 45
24x = 46
x = 46/24
Simplifying, we get:
x = 23/12
Therefore, the solution to the equation is:
x = 23/12.
log base a (M/N) = log base a M - log base a N,
we can rewrite the given equation as:
log3 (4x+1) - log3 (3x-5) = 2
log3 [(4x+1)/(3x-5)] = 2
3^2 = 9, so we can rewrite the equation as:
(4x+1)/(3x-5) = 9
Multiplying both sides by 3x-5, we get:
4x + 1 = 9(3x-5)
Simplifying and solving for x, we get:
4x + 1 = 27x - 45
24x = 46
x = 46/24
Simplifying, we get:
x = 23/12
Therefore, the solution to the equation is:
x = 23/12.