log3(4x+1)-log3(3x-5)=2

5 answers

log3(4x+1)-log3(3x-5)=2
log3( (4x+1)/(3x-5)) = 2

(4x+1)/(3x-5) = 3^2 = 9
27x - 45 = 4x + 1

carry on
Abigail
If log10y+3log10*=2, Express y in term of x.
Solve the equation log3,4x+1-log3,3x-5=2
Using the logarithmic identity,

log base a (M/N) = log base a M - log base a N,

we can rewrite the given equation as:

log3 (4x+1) - log3 (3x-5) = 2

log3 [(4x+1)/(3x-5)] = 2

3^2 = 9, so we can rewrite the equation as:

(4x+1)/(3x-5) = 9

Multiplying both sides by 3x-5, we get:

4x + 1 = 9(3x-5)

Simplifying and solving for x, we get:

4x + 1 = 27x - 45

24x = 46

x = 46/24

Simplifying, we get:

x = 23/12

Therefore, the solution to the equation is:

x = 23/12.
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