log(x) + log(x − 3) = 1
log(x(x-3)) = 1
x(x-3) = 10^1
x^2 - 3x - 10 = 0
(x - 5)(x + 3) = 0
x = 5 or x = -3
but in logx , x > 0
so x = 5
log(x) + log(x − 3) = 1
Encontrar x
2 answers
(x - 5)(x + 2) = 0