Asked by Anonymous
log_3(2x - 1) = 2, Find x.
Here's what I've done:
log_3(2x) * log_3(1) = 2
log2x/log3 * log1/log3 = 2
trial and error...
log2 (2*1.4)/log3 * 0 = 2.03...
x = 1.4
I think I did it wrong because anything that multiplies with 0 gives you 0...
Here's what I've done:
log_3(2x) * log_3(1) = 2
log2x/log3 * log1/log3 = 2
trial and error...
log2 (2*1.4)/log3 * 0 = 2.03...
x = 1.4
I think I did it wrong because anything that multiplies with 0 gives you 0...
Answers
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