1/log_2(X) + 1/log_3(x) + 1/log_4(x) +1/log_5(x) =log

Let x = log_2 1/8 Write the exponential form of the equation and solve the equation for x.

Let x = log_2 1/8 Write the exponential form of the equation and solve the equation for x....

solve the logarithm log_2 (x -1)- log_2(5x +1) = -3 I got -3, is this correct???????

log_(1/4)⁡〖1/64〗+log_2⁡〖1/32〗-log_9⁡〖(75+x)〗-log_27⁡9=(-14)/3

Simplify exactly log_2 1/16

Prove. 3/(log_2 (a)) - 2/(log_4 (a)) = 1/(log_(1/2)(a))

Graph of f(x)=log_2(x) has been transformed to g(x)=alog_2(x)+k. The transformed image passes throug...

Solve for x and y if log_2(x+y)=log_3(3x+4y)=3

log_2 16

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