Asked by Bethany
Graph of f(x)=log_2(x) has been transformed to g(x)=alog_2(x)+k. The transformed image passes through the points (1/4,-9) and (16,-6). Determine a and k.
No idea. Thanks!
No idea. Thanks!
Answers
Answered by
Steve
well, did you not just plug in the points given?
g(1/4) = -9, so
-2a+k = -9
g(16) = -6, so
4a+k = -6
a = 1/2
k = -8
g(x) = 1/2 log_2(x) - 8
g(1/4) = -9, so
-2a+k = -9
g(16) = -6, so
4a+k = -6
a = 1/2
k = -8
g(x) = 1/2 log_2(x) - 8
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.