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Graph of f(x)=log_2(x) has been transformed to g(x)=alog_2(x)+k. The transformed image passes through the points (1/4,-9) and (16,-6). Determine a and k.

No idea. Thanks!
9 years ago

Answers

Steve
well, did you not just plug in the points given?

g(1/4) = -9, so
-2a+k = -9

g(16) = -6, so
4a+k = -6

a = 1/2
k = -8

g(x) = 1/2 log_2(x) - 8
9 years ago

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