Log 1728 to the base √3

Answer 1

since √3 = 3^(1/2)
log_√31728 = 2log₃1728

now, 1728 = 12^3 = 2^3 * 3^3 so

2log₃1728 = 2(log₃2 + 3)
Not sure just where you're going with this

Answer 2

oops. That would be
2(3log₃2 + 3)

Answer 3

1728 = 12^3 = 4^3 * 3^3
etc