first of all you dont need () those for the five so that's one, and you dont need the () for the 1/x
your problem should look like this
y=5(3+e^1x)
either that that idk
Locate the discontinuities of the function
y=(5)/(3+e^(1/x))
2 answers
you do need the () around 1/x, since powers are done first, and you don't want (e^1)/x
3+e^(1/x) is never zero, so there are no discontinuities because of a zero denominator.
However, since 1/x is undefined at x=0, there is a jump there.
lim as x->0- = 5/3
lim as x->0+ = 0
3+e^(1/x) is never zero, so there are no discontinuities because of a zero denominator.
However, since 1/x is undefined at x=0, there is a jump there.
lim as x->0- = 5/3
lim as x->0+ = 0