liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. Suppose 7.8 g of hexane is mixed with 48.4 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction.

Answer 1

2C6H14 + 19O2 --------> 12CO2 + 14H2O

7.8g*(1 mole/86.18g)= moles of Hexane

moles of Hexane*(12 moles of CO2/2 moles of C6H18)= moles of CO2

moles of CO2*(44.01g/mole)= max mass of CO2

Answer with the appropriate number of significant figures