Line MO bisects <LMN, m<LMN =6x-28,m<LMO=x+34. Find m<NMO

Answer 1

since LMO+NMO = LMN,

x+34 + NMO = 6x-28
But, MO bisects LMN, so LMO=NMO
x+34 + x+34 = 6x-28
2x+68 = 6x-28
4x = 96
x = 24

Now you can figure the actual degree measures.

Answer 2

That would makem it

24 + 34 =58 T NMO = 6(24)-28

58 + nmo = 144 - 28 = 119

116- 58 = 58

Thank you

Answer 3

neature

Answer 4

thx