Asked by eric
Lim x to 3 (-x^2)/((x^2)- 6x + 9)
substitution i get -9/0
factoring i get same answer
would that mean the answer is infinity?
if not how could i prove that it isn't infinity
substitution i get -9/0
factoring i get same answer
would that mean the answer is infinity?
if not how could i prove that it isn't infinity
Answers
Answered by
Damon
Often if you do not trust your answer, try numbers for example
say x = 3.1
-9.61 / (9.61 - 18.6 + 9)
= - 9.61 / .01 = -961
next try x = 3.01
but you get the idea. I think your answer is correct. The result is -9/0 which is undefined or infinite.
say x = 3.1
-9.61 / (9.61 - 18.6 + 9)
= - 9.61 / .01 = -961
next try x = 3.01
but you get the idea. I think your answer is correct. The result is -9/0 which is undefined or infinite.
Answered by
Steve
since x^2-6x+9 = (x-3)^2 the denominator -> 0 while the numerator does not. So, you are correct that the limit is undefined.
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