Asked by Lauren
                use variable substitution and factoring to find all of the roots of each equation. 
x^4-9x^2+18=0
how do you do this??
            
        x^4-9x^2+18=0
how do you do this??
Answers
                    Answered by
            DanH
            
    you need, of course, to factor this.  
Start by doing this:
(x^2 - )(x^2 - ) =0
Can you fill in the blanks?
    
Start by doing this:
(x^2 - )(x^2 - ) =0
Can you fill in the blanks?
                    Answered by
            Lauren
            
    is it (x^2 - 6) (x^2 - 3) ??
    
                    Answered by
            DanH
            
    yes!!  so you have it factored.  Then to get the "roots," set each one equal to 0.  
    
                    Answered by
            Lauren
            
    so then its x^2-6 =0 and ^2-3=0 and the don't i put the root sign over the x^2 to get rid of the x^2? and then i end up with x + or - the suare root of 6 = 0 or is that wrong??
    
                    Answered by
            DanH
            
    yes....
you have x^2 - 6 = 0,
so, x = + and - sqrt6
AND
x^2 - 3 = 0,
so, x also = + and - sqrt3
    
you have x^2 - 6 = 0,
so, x = + and - sqrt6
AND
x^2 - 3 = 0,
so, x also = + and - sqrt3
                    Answered by
            Lauren
            
    so is that it?? simple as that?
    
                    Answered by
            DanH
            
    yup, simple as that!!
    
                    Answered by
            Lauren
            
    but then the directions say variable substitution
    
                    Answered by
            DanH
            
    I'm sorry.  I really don't know what they mean by "variable substitution!"
    
                    Answered by
            Lauren
            
    alright thanks anyway
    
                    Answered by
            bre
            
    x^2-x-?=(x+2)(x-?)
    
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