Asked by Lauren
use variable substitution and factoring to find all of the roots of each equation.
x^4-9x^2+18=0
how do you do this??
x^4-9x^2+18=0
how do you do this??
Answers
Answered by
DanH
you need, of course, to factor this.
Start by doing this:
(x^2 - )(x^2 - ) =0
Can you fill in the blanks?
Start by doing this:
(x^2 - )(x^2 - ) =0
Can you fill in the blanks?
Answered by
Lauren
is it (x^2 - 6) (x^2 - 3) ??
Answered by
DanH
yes!! so you have it factored. Then to get the "roots," set each one equal to 0.
Answered by
Lauren
so then its x^2-6 =0 and ^2-3=0 and the don't i put the root sign over the x^2 to get rid of the x^2? and then i end up with x + or - the suare root of 6 = 0 or is that wrong??
Answered by
DanH
yes....
you have x^2 - 6 = 0,
so, x = + and - sqrt6
AND
x^2 - 3 = 0,
so, x also = + and - sqrt3
you have x^2 - 6 = 0,
so, x = + and - sqrt6
AND
x^2 - 3 = 0,
so, x also = + and - sqrt3
Answered by
Lauren
so is that it?? simple as that?
Answered by
DanH
yup, simple as that!!
Answered by
Lauren
but then the directions say variable substitution
Answered by
DanH
I'm sorry. I really don't know what they mean by "variable substitution!"
Answered by
Lauren
alright thanks anyway
Answered by
bre
x^2-x-?=(x+2)(x-?)