lim ln(y-1)

Question

y->1+

The answer is negative infinity but how do I show the logic of proving that it's negative infinity? I plugged in "1" to the function and got ln(0) which is obviously impossible? Thanks in advance

Answer 1

so put in ln .01 and ln .00001 etc
or
say
j = ln z

e^j = z
e^j = 0 + a little
e^-oo = 1/e^oo --->0 + a little

Answer 2

So I can just say for example, plug values as y gets closer to 1 and solve for the function and notice that the function is getting smaller and smaller (negative) and therefore negative infinity?