Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 5.0 m/s. Once free of this area, it speeds up to 13 m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed.

What is the final speed?

asked by Noah

3 years ago

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2 answers

a = (13 - 5) / 8 = 1 m/s^2
v = 13 + a t = 13 + 1 * 16
= 29 m/s

answered by Anonymous

2

9

no its 25

answered by Jim

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Question

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 5.0 m/s. Once free of this area, it speeds up to 13 m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed.

What is the final speed?

2 answers

a = (13 - 5) / 8 = 1 m/s^2
v = 13 + a t = 13 + 1 * 16
= 29 m/s

no its 25

What is the final speed?

Jim · Accepted Answer

no its 25

Anonymous · Answer

a = (13 - 5) / 8 = 1 m/s^2 v = 13 + a t = 13 + 1 * 16 = 29 m/s