Asked by Pamela

Let x = log_2 1/8

Write the exponential form of the equation and solve the equation for x.

Does this work? Thanks!

Exponential form is 2^-3=1/8

To Check:
2^-3=1/2^3=1/8


Answers

Answered by MathMate
Please continue with post below, you are almost there!
http://www.jiskha.com/display.cgi?id=1249473232
Answered by Pamela
x = log_ 2 2^-3

? I am lost now. I really thought I had it from what I just posted.

Exponential form is 2^-3 = 1/8 This isn't correct?

To Check:
2^-3=1/2^3=1/8
Answered by MathMate
Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding.

You also need to do the second part: " and solve the equation for x."

You are very close to finishing, keep it up.
Answered by Pamela
Solve for x i got, the exponential is the problem for me...Here is what i got for x.

To Solve:

1/8=8^-1
8=2^3
1/8=2^3^-1=8^-1
=2^-3
Log_2 1/8 = log_2 2^-3

=-3log_2 2

x =-3

To Check:

2^x=1/8= 2^-3

x=-3
Answered by MathMate
Correct!
Answered by Pamela
Now what about the Exponential form
?

2^-3 = 1/8 This isn't correct? If not then how do i show Let x = log_2 1/8 in exponential form?
Answered by MathMate
"Algebra Help - MathMate, Wednesday, August 5, 2009 at 6:41pm

Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding. "

The exponential form has to be correct for you to proceed with the second part, otherwise the second part will not be correct.
Answered by Pamela
Thank you this really helps! So I got

Exponential form is 2^-3 = 1/8

and To solve x = -3 So this is all of it?
Answered by MathMate
That's all there is to it.

If you have time, read up and understand of the identities listed earlier. You'll be glad you did when exam comes around.
Answered by Pamela
Thanks! You have been a BIG help! I will do that!
Answered by MathMate
It's been a pleasure!
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