Let x = log_2 1/8

Question

Write the exponential form of the equation and solve the equation for x.

Answer 1

Here are a few hints:
a.a.a = a³
(1/a).(1/a).(1/a) = a^-3
log_a a^b = b
For example:
log₁₀100 = log₁₀10² = 2

Answer 2

2x = 2^log2(1/8)

2x = (1/8)

Are these acceptable answers?

Answer 3

You're getting there, but not exactly yet.
Try writing
1/8
= 1/2³
= 2^-3
and apply one of the above identities given in the hint.

Answer 4

Does this work? Thanks!

Exponential form is 2^-3=1/8

To Check:
2^-3=1/2^3=1/8

Answer 5

So far so good, but you have to continue to solve for x, such as:
x = log₂2^-3
How does that compare with the identity above:
log_a a^b = b

Answer 6

Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding.

You also need to do the second part: " and solve the equation for x."

You are very close to finishing, keep it up.