Asked by Ashley
Let the set X = (-1, 1)
Define f: X--->R(set of real numbers) such that f(x) = x/(x-1)
Check if f is onto.
Let y = x/(x-1)
Then, x = y/(y-1)
Since y belongs to R, y=1 would result in an undefined value for x.
Hence, can we conclude f is not onto?
Define f: X--->R(set of real numbers) such that f(x) = x/(x-1)
Check if f is onto.
Let y = x/(x-1)
Then, x = y/(y-1)
Since y belongs to R, y=1 would result in an undefined value for x.
Hence, can we conclude f is not onto?
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