Let the sample space be Upper S equals StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 EndSet

Question

.
Suppose the outcomes are equally likely. Compute the probability of the event Eequals
​"an
odd

​number."

Answer 1

There are 6 outcomes in the sample space, and out of those, there are 3 odd numbers (1, 3, and 5).

Since the outcomes are equally likely, the probability of an odd number is given by the number of favorable outcomes (3) divided by the total number of outcomes (6).

Therefore, the probability of the event E, "an odd number," is 3/6 or 1/2.