Let the sample space be Upper S equals StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 EndSet

Question

.
Suppose the outcomes are equally likely. Compute the probability of the event Eequals
​"an
odd

number less than 7
​."

Answer 1

The event E consists of the numbers 1, 3, and 5.

Since there are 3 outcomes in event E and 10 outcomes in the sample space S, the probability of event E is given by:

P(E) = Number of outcomes in E / Number of outcomes in S = 3 / 10 = 0.3

Therefore, the probability of the event E, "an odd number less than 7," is 0.3.