perpendicular bisector of AB crosses at the midpoint.
The midpoint of AB is (27/2 , 11/2)
2x-4y = 27 - 22 = 5
Let the line p be the perpendicular bisector of A = (24, 7) and B = (3, 4). Given that AB meets p at C = (x, y), what is 2x - 4y?
2 answers
Clearly the perpendicular bisector has to meet AB at the midpoint of AB, so
you need the midpoint of AB which is
C( (24+3)/2 , (7+4)/2 ) = C(27/2 , 11/2)
that is x = 27/2 and y = 11/2
2x - 4y
= 27 - 22 = 5
you need the midpoint of AB which is
C( (24+3)/2 , (7+4)/2 ) = C(27/2 , 11/2)
that is x = 27/2 and y = 11/2
2x - 4y
= 27 - 22 = 5