massneeded= molmass*volume*molarity
I would memorize that, it saves a lot of time when making solutions.
IT comes from
molarity= (mass/molmass)/volumesolution
let me rephrase my question. A Mole of ethyl alcohol weights 46g.How many grams of ethyl alcohol are needed to produce 1 L of a 2 milimolar solution? I know the answer is 0.092g but I don't know how to derive it
1 answer
1 answer