log 6/25= log (3*2)/(5^2)
= log 3 + log2 - 2 log5
let log2=a, log3=b, and log5=c. express the indicated logarithm in terms of a, b, and c.
log6/25
log 100
2 answers
log 100
= log(25*4)
= log 25 + log 4
= log 5^2 + log 2^2
= 2log5 + 2log2
= 2c + 2a
= log(25*4)
= log 25 + log 4
= log 5^2 + log 2^2
= 2log5 + 2log2
= 2c + 2a