Let f(x) = e^x – 2 + 3
a. Describe in words how the graph of f can be obtained from the graph of y = e^x.
b. What is the domain of f?
c. What is the range of f?
d. What is the y-intercept? State the approximation to 2 decimal places (i.e., the nearest hundredth).
2 answers
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I must have a twin! lol...Hey can you tell me if this is correct?
(a) Describe in words how the graph of f can be obtained from the graph of y = e^x.
The graph of f can be obtained from the graph of y = e^x by off setting the graph by one.
(b) What is the domain of f? x= {x|-&<x<+&, xEReal} X is the element of real numbers this means Infinite.
Domain of f is all real values of f.
(c) What is the range of f? The range is all the real numbers except three.
(d) What is the y-intercept? State the approximation to 2 decimal places (i.e., the nearest hundredth).
y intercept is when x is zero. e^-2 + 3 or about 1/e^2 + 3 =approximately 1/6 + 3 + 3.15 checking that in a calculator:???????????????????
IF X=0 THEN Y=e^ (-2) +3
e=2.7
2.7^-2+3=1/2.7^2+3= 3.14
(a) Describe in words how the graph of f can be obtained from the graph of y = e^x.
The graph of f can be obtained from the graph of y = e^x by off setting the graph by one.
(b) What is the domain of f? x= {x|-&<x<+&, xEReal} X is the element of real numbers this means Infinite.
Domain of f is all real values of f.
(c) What is the range of f? The range is all the real numbers except three.
(d) What is the y-intercept? State the approximation to 2 decimal places (i.e., the nearest hundredth).
y intercept is when x is zero. e^-2 + 3 or about 1/e^2 + 3 =approximately 1/6 + 3 + 3.15 checking that in a calculator:???????????????????
IF X=0 THEN Y=e^ (-2) +3
e=2.7
2.7^-2+3=1/2.7^2+3= 3.14
0 answers