well, does f(4) = 2?
yes.
and, your solution of (x+6)/2 is correct
Let f(x) = 2x − 6. Solve f^−1(x) when x = 2.
I think it is 4.
f(x) = 2x - 6
y = 2x - 6
x = 2y - 6
+6 + 6
x + 6 = 2y
----- ----
2 2
x + 6
----- = y or f^-1(x)
2
x = 2:
2 + 6 8
----- = ---
2 2
8
--- = 4
2
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