Asked by Z32
Let f be the function defined by f(x)=2x+11-3e^x
If the equation of the tangent line to the graph of f at the point (0,8) is given by y=mx+b then:
m=?
and b=?
If the equation of the tangent line to the graph of f at the point (0,8) is given by y=mx+b then:
m=?
and b=?
Answers
Answered by
Quidditch
For the standard line equation,
y=mx+b
m is the slope of the line
b is the y intercept (where x=0)
Take the derivative of the equation. Use that to find the slope of the tangent at (0,8). Once you have the slope and one point (0,8) you can solve for the b.
y=mx+b
m is the slope of the line
b is the y intercept (where x=0)
Take the derivative of the equation. Use that to find the slope of the tangent at (0,8). Once you have the slope and one point (0,8) you can solve for the b.
Answered by
Z32
I just need help finding the derivative of f(x). The 3e^x is tripping me out.
Answered by
Damon
if
y = 3e^x
then
dy/dx = 3 e^x
because
d/dx e^u = e^u du/dx
y = 3e^x
then
dy/dx = 3 e^x
because
d/dx e^u = e^u du/dx
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