Asked by Anonymous
                A function is defined by 
y= x^3/48 + 1/x
(A) Find dy/dx
- my answer: 1/16x^2-x^-2
(B) Find d^2y/dx^2
- my answer: 1/8x+2x^-3
C) use your answer to (A) to find the x coordinate of the two stationary points.
D) use your answer to (B) to determine whether each point is a maximum or a minimum
Please help
Thankyou :)
            
        y= x^3/48 + 1/x
(A) Find dy/dx
- my answer: 1/16x^2-x^-2
(B) Find d^2y/dx^2
- my answer: 1/8x+2x^-3
C) use your answer to (A) to find the x coordinate of the two stationary points.
D) use your answer to (B) to determine whether each point is a maximum or a minimum
Please help
Thankyou :)
Answers
                    Answered by
            Damon
            
    C) 
the function graph is horizontal when dy/dx = 0
(1/16) x^2 -1/x^2 = 0
(1/16) x^4 = 1
x^4 = 16
x = + or - 2
D)
at x = -2
d^2y/dx^2 = (1/8)(-2) +2(1/-8)
negative so headed down, a maximum
at x = + 2
POSITIVE SO HEADED UP, MINIMUM
    
the function graph is horizontal when dy/dx = 0
(1/16) x^2 -1/x^2 = 0
(1/16) x^4 = 1
x^4 = 16
x = + or - 2
D)
at x = -2
d^2y/dx^2 = (1/8)(-2) +2(1/-8)
negative so headed down, a maximum
at x = + 2
POSITIVE SO HEADED UP, MINIMUM
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