Let C be a circle that passes through the origin. Show that we can find real numbers s and t such that C is the graph of

r = 2s*cos(theta + t)

I think that I could start by writing it like R^2=(x-h)^2+(y-k)^2 where R is the radius of the circle, but I don't what to do with that info.

4 answers

no help from my earlier comments?

http://www.jiskha.com/display.cgi?id=1461018078
Sorry, they just seem unclear, and you seem unsure of your final answer... And I didn't think you would respond to the original thread so I resposted
Never mind, I think I get it now
good. I thought it would make sense if you looked at it a while.