Let a be -1/6 and let b be 1/2. Let x be the sum of the reciprocals of a and b, let y be the product of the reciprocals of a and b, and let z be twice the reciprocal of a divided by the reciprocal of b. Calculate x+y+z.

Answer 1

reciprocal of -1/6
=6
and that of 1/2=2
a=-6
b=2
a+b=x
-6+2=x
x=-4
y=a*b
y=-6*2
y=-12
z=2(a)/b
z=2*-6/2
z=-6
now x+y+z=??

Answer 2

97

Answer 3

the answer is -22
I just did the problem