[x,3,3]= 3 2.x.3+3.3=3 3[2x+3]=3
2x+3=3/3=1 2x=1-3 2x=-2 x=-2/2 =-1 x=-1
Let [a b c] be defined by [a b c]= 2ab +3c for all integers a,b, and c. If [x 3 3] = 3, what is the value of x?
2 answers
if [a b c} = 2ab + 3c , then
[x 3 3) = 2(x)(3) + 3(3) = 3
6x + 9 = 3
6x = -6
x = -1
[x 3 3) = 2(x)(3) + 3(3) = 3
6x + 9 = 3
6x = -6
x = -1